To find the area of the triangle with vertices at \((6, 2)\), \((4, 6)\), and \((1, 2)\), we can use the formula for the area of a triangle given its vertices \((x_1, y_1)\), \((x_2, y_2)\), and \((x_3, y_3)\):
\[ \text{Area} = \frac{1}{2} \left| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right| \]
Assigning the coordinates:
- \((x_1, y_1) = (6, 2)\)
- \((x_2, y_2) = (4, 6)\)
- \((x_3, y_3) = (1, 2)\)
We can now plug in the values:
\[ \text{Area} = \frac{1}{2} \left| 6(6 - 2) + 4(2 - 2) + 1(2 - 6) \right| \]
Calculating the individual terms:
- \(6(6 - 2) = 6 \times 4 = 24\)
- \(4(2 - 2) = 4 \times 0 = 0\)
- \(1(2 - 6) = 1 \times -4 = -4\)
Putting it all together:
\[ \text{Area} = \frac{1}{2} \left| 24 + 0 - 4 \right| = \frac{1}{2} \left| 20 \right| = \frac{1}{2} \times 20 = 10 \]
Therefore, the area of Fiona’s triangle is \(\boxed{10}\) square units.