Fine the real and imaginary part of 6i/(2-i)²

4 answers

6 i/(2-i) * 1/(2-i)

6i (2+i)/ [ (2-i)(2+i) ] * (2+i)/[ (2-i)(2+i) ]

(12 i -6) /[ 4+1 ] * (2+i)/ [ 4+1 ]

(24 i-12-12 -6 i)/25

-24/25 + (18 /25) i
Please which is the real and Aldo the imaginary
Hey, you better take the course
if you have
x + y i
x is real part
y i is imaginary part
see:
https://www.mathsisfun.com/numbers/complex-numbers.html
Thanks friends. I really appreciate . now I understand