To find the equation of the axis of symmetry for the parabola given by the equation \( y = x^2 - 3x + 2 \), we can use the formula for the axis of symmetry, which is given by:
\[ x = -\frac{b}{2a} \]
In this equation, \( a \) and \( b \) are the coefficients from the standard form of a quadratic equation \( y = ax^2 + bx + c \).
For the given equation \( y = x^2 - 3x + 2 \):
- \( a = 1 \)
- \( b = -3 \)
Now we can substitute these values into the formula:
\[ x = -\frac{-3}{2(1)} = \frac{3}{2} \]
Thus, the equation of the axis of symmetry for the parabola \( y = x^2 - 3x + 2 \) is:
\[ x = \frac{3}{2} \]