Asked by Kayleigh
finding the acceleration of a simple pendulum
g= 4pi^2 x length/T^2
T^2= 2.28
length= 70cm
g= 4pi^2 x length/T^2
T^2= 2.28
length= 70cm
Answers
Answered by
drwls
Acceleration in what direction? horizontal? vertical? centripetal? angular?
Acceleration at what time? What is the amplitude of the oscillation? That affects the answer.
The horizontal (x) acceleration for small displacements varies with time as
ax = -(amplitude)*w^2*sin wt
where
w = sqrt(g/L)
Acceleration at what time? What is the amplitude of the oscillation? That affects the answer.
The horizontal (x) acceleration for small displacements varies with time as
ax = -(amplitude)*w^2*sin wt
where
w = sqrt(g/L)
Answered by
Kayleigh
its a simple pendulum brass ball.
hung from a string swinging with no applied pressure. the pendulum was drawn into the air 20 cm from the center. and swings to the other side. same distance 20 cm
hung from a string swinging with no applied pressure. the pendulum was drawn into the air 20 cm from the center. and swings to the other side. same distance 20 cm
Answered by
drwls
So the amplitude is 20 cm. You can use the formula I gave for the x acceleration, but you never said which acceleration you want.
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