Find

y'and y''.
y=x^1/2 ln(x)

1 answer

Just use the product rule

y = √x lnx
y' = lnx/(2√x) + 1/√x
y" = 1/(2x^(3/2)) + lnx((-1/4)x^(-3/2)) + (-1/2)x^(-3/2)
= -lnx/(4x^(3/2))

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