find y' and y''

Question

y = ln(x+(square root of (9+x^2))

Answer 1

is the square root in parenthesis within the ln? on one side it is and on the other its not

Answer 2

I figure it's

y = ln (x+√(9+x^2))
y' = 1/(x+√(9+x^2)) (1 + x/√(9+x^2))
= 1/√(9+x^2)
y" = -x/(9+x^2)^(3/2)