find y' and y'' for the equation below.
Show work please!!!
y= (x^3)/((x+1)^2)
4 answers
https://www.wolframalpha.com/input/?i=derivative+of+%28x^3%29%2F%28%28x%2B1%29^2%29+
[(x+1)^2 (3 x^2)-x^3 (2)(x+1)] /(x+1)^4
[(x+1)(3x^2) - 2 x^3 ]/ (x+1)^3
[ 3 x^3 + 3 x^2 -2 x^3 ] / (x+1)^3
[ x^3 + 3 x^2] /(x+1)^3
x^2 (x+3) / (x+1)^3
[(x+1)(3x^2) - 2 x^3 ]/ (x+1)^3
[ 3 x^3 + 3 x^2 -2 x^3 ] / (x+1)^3
[ x^3 + 3 x^2] /(x+1)^3
x^2 (x+3) / (x+1)^3
then do it again :)
https://www.wolframalpha.com/input/?i=derivative+of+x^2%28x%2B3%29%2F%28x%2B1%29^3
6x / (x+1)^4
6x / (x+1)^4
1 answer