f'(x) = x(2logx - 1)/(logx)^2
So, since f and f' are not defined at x=0,
f'(x) = 0 when
2logx = 1
logx = 1/2
x = √e
f(√e) = e/(1/2) = 2e
See the graph at
http://www.wolframalpha.com/input/?i=%28x^2%29%2F%28ln%28x%29%29+for+x+%3D+0..3
Find x-value of all points where function has relative extrema and find the Values of these extrema.
f(x)= (x^2)/(ln(x))
1 answer