find x in DMS if 2sinx-1=cscx

1 answer

2sinx-1=cscx
2sin(x)-1 = 1/sin(x)
2sinĀ²(x)-sin(x)-1=0
(2sin(x)+1)(sin(x)-1)=0
sin(x)=-1/2 or sin(x)=1
can you take it from here?

Note that sin(x) is positive in the first and second quadrants.
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