Work = F * d = Mg * d = 25*9.8 * 2 = 490 J.
sin30 = 2/L. L = 4 m. = Length of incline.
Fp = Mg*sin30 = 25*9.8*sin30 = 122.5 N. = Force in parallel with
the incline.
Work = Fp*L = 122.5 * 4 = 490 J.
Find work done when 25kg weight lifted to a vertical height of 2m from the ground carrying to the same place by pushing it up and inclined plane make the angle of 30 degree (g=9.8)
8 answers
Why we multiply w.d with length of the incline
explain 2 part of the answer
Explain second point
Explane your answer
Why you multiplied by 4 when displacement is 2 m
Right
Why u multiply by 4 ðŸ˜
3 answers