f(x) = 0 when lnx = 2
x = e^2 = 7.389 when f(x) = 0
f(x)> 0 for x > e^2
f(x) <0 for x < e^2
find where f(x)<0 and f(x)>0
f(x)=xlnx-2x
3 answers
x*ln(x)-2x<0
x*ln(x)<2x Divided with x
ln(x)<2
e^2=7.389 x<7.389
x*ln(x)-2x>0
x*ln(x)>2x Divided with x
ln(x)>2
e^2=7.389 x>7.389
x*ln(x)<2x Divided with x
ln(x)<2
e^2=7.389 x<7.389
x*ln(x)-2x>0
x*ln(x)>2x Divided with x
ln(x)>2
e^2=7.389 x>7.389
Why post the same answer over 3 hours later?