log1/2(x-1)+log1/2(x+1)-log1/√2(7-x)=1
You seriously need to learn how to use parentheses. Also, the final result will depend on the base of the logarithms. I shall assume base 10.
Assuming you meant
log(1/(2(x-1)))+log(1/(2(x+1)))-log(1/(√2(7-x)))=1
log (1/(2(x-1)) * 1/(2(x+1)) * √2(7-x)) = 1
1/(2(x-1)) * 1/(2(x+1)) * √2(7-x) = 10
I'll let you solve the cubic in any way you like, but somehow I feel the question has been garbled.
I suggest you type in your equation at wolframalpha.com and see how it interprets your text. Then use enough parentheses to make it come out right.
Find value of x for log1/2(x-1)+log1/2(x+1)-log1/√2(7-x)=1
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1 answer