Find using substitution:

Question

∫ 1/[x(1+lnx)^2] dx

I'm not sure what substitution to use.

Answer 1

maybe something like

let z = ln x
dz /dx = 1/x
dx = x dz

∫ 1/[x(1+lnx)^2] dx

∫ dz/[ 1+z]^2

Answer 2

Don't worry, I've got it. I used the substitution u = 1 + lnx and got the answer