sin θ= sqrrt3/2
This is just your standard pi/3. So, pi/3 and 2pi/3
b. 4pi/3, 5pi/3
Find two values of theta that satisfy the equation. give your answers in degrees (0degrees <theta<360degrees ) and radians (0<theta<2pi)
a. sin θ= sqrrt3/2
b.sin θ= - sqrrt3/2
1 answer
2 answers