Find two positive numbers that satisfy the given requirements.

Question

The product is 147 and the sum of the first number plus 3 times the second number is a minimum.

Answer 1

a*b = 147
147 = 3*7*7

So, the only choices for a*b are

3*49
49*3
7*21
21*7
1*147
147*1

You can figure which gives minimum a+3b