Find two numbers whose difference is 132 and whose product is a minimum.

Answer 1

smaller number --- x
larger number ----- x + 132

product=P=x(x+132)
= x^2 + 132x
dP/dx = 2x + 132
=0 for a min of P
2x = -132
x = -66

the smaller is -66
the larger -66+132 or +66

the two numbers are -66 and +66

Answer 2

didn't understand that method

Answer 3

its very smart way for a explanation but doesn't really make sense