Find two consecutive positive integers whose product is 132.
2 answers
11*12 = 132
x(x+1)=132
x^2+x=132
x^2+x+132=0
(x+12)(x-12)=0
x=-12 x=12
x^2+x=132
x^2+x+132=0
(x+12)(x-12)=0
x=-12 x=12
1 answer