find two consecutive positive integers such that their product added to four times the smaller integer equals 36

Answer 1

let the two numbers be x and x+1
4x + x(x+1) = 36
x^2 + 5x - 36 = 0
(x+9)(x-4) = 0
x = 4 or x = -9, but x>0

x = 4

the two numbers are 4 and 5