consecutive number are one apart
so let the first be x
then the 2nd is x+1
their squares differ by 1 ---> (x+1)^ - x^2 = 31
x^2 + 2x + 1 - x^2 = 31
2x = 30
x = 15
so the first is 15, the next one is 16
check:
16^2 - 15^2
= 256 - 225
= 31
all is good!
Find two consecutive numbers who squares differ by 31 I got 2 and 31 but I got it wrong someone help me please
3 answers
Write an inequality for the statement:The average temperature in January was 11° C which is warmer than Decembers average temperature of -1° C.
We know in January it was 11 degrees Celsius
In December it is -1 degree Celsius
Take that and put -1 on the left.
Now put a < sign next to the one.
After that put the 11 next to the < sign.Now you have your inequality of -1<11.
In December it is -1 degree Celsius
Take that and put -1 on the left.
Now put a < sign next to the one.
After that put the 11 next to the < sign.Now you have your inequality of -1<11.