Find three consecutive odd integers such that the square of the first increased by product of the other two is 224.

Answer 1

let the middle number be x
then the 1st is x-2
and the 3rd is x+2

(x-2)^2 + x(x+2) = 224
x^2 - 4x + 4 + x^2 + 2x = 224
2x^2 -2x - 220 = 0
x^2 - x - 110 = 0
(x-11)(x+10) = 0
x = 11 or x = -10, but x is to be odd
so
x = 11
and the three numbers are 9, 11, and 13

check:
9^2 + 11(13) = 224 , YEAH!

Answer 2

i got this so correct omg im so happy