Find three consecutive integers such that, the sum of the first and four times the third is 98.

Question

Thank you!

Answer 1

Numbers are:

A

B = A + 1

C = B + 1 = A + 1 + 1 = A + 2

The sum of the first and four times the third is 98 means;

A + 4 C = 98

A + 4 ∙ ( A + 2 ) = 98

A + 4 A + 8 = 98

5 A + 8 = 98

Subtract 8 to both sides

5 A = 90

A = 90 / 5 = 18

So numbers are:

A = 18

B = A + 1 = 18 + 1 = 19

C = A + 2 = 18 + 2 = 20

18 , 19 , 20