Find the zeros of the quadratic equation y = 6x + 8x + 7 using one of the following methods: factoring, square roots, complete the square, or quadratic formula

Answer 1

Let's first rewrite the given quadratic equation \( y = 6x + 8x + 7 \) in standard form.

Combine the like terms:

\[ y = (6x + 8x) + 7 = 14x + 7 \]

Next, we set the equation equal to zero to find the zeros:

\[ 14x + 7 = 0 \]

Now, let's solve for \( x \):

1. Subtract 7 from both sides:

\[ 14x = -7 \]

2. Divide both sides by 14:

\[ x = -\frac{7}{14} = -\frac{1}{2} \]

So, the zero of the equation is:

\[ x = -\frac{1}{2} \]

This equation simplified to a linear equation, indicating that it has only one zero, which is \(-\frac{1}{2}\).