To find the zeros of the function, we set y equal to zero and solve for x:
0 = 12x^3 - 12x
Factoring out 12x, we get:
0 = 12x(x^2 - 1)
Setting each factor equal to zero, we have:
12x = 0 or x^2 - 1 = 0
Solving the first equation, we find that x = 0. This is a zero of multiplicity 1.
Solving the second equation, we have:
x^2 = 1
Taking the square root of both sides, we get:
x = 1 or x = -1
Both 1 and -1 are zeros of multiplicity 1.
Therefore, the zeros of the function y = 12x^3 - 12x are x = 0 (multiplicity 1), x = 1 (multiplicity 1), and x = -1 (multiplicity 1).
Find the zeros of the function. State the multiplicity of multiple zeros.
y=12x^3-12x
1 answer
1 answer