To find the zeros of the function, we set y equal to zero and solve for x:
0 = 6x^3 - 6x
Next, we can factor out a common factor of 6x from both terms:
0 = 6x(x^2 - 1)
Now, we have two factors: 6x and (x^2 - 1).
Setting each factor equal to zero, we have:
6x = 0 --> x = 0
x^2 - 1 = 0
Using the difference of squares formula, we have:
(x - 1)(x + 1) = 0
Setting each factor equal to zero, we have:
x - 1 = 0 --> x = 1
x + 1 = 0 --> x = -1
Therefore, the zeros of the function are: x = 0, x = 1, and x = -1.
The multiplicity of each zero is 1, meaning each zero appears only once in the factored form of the function.
Find the zeros of the function. State the multiplicity of multiple zeros.
y=6x^3-6x
1 answer