2x^2 − 3x − 9 = 0
factoring ... (2x + 3)(x - 3) = 0
2x + 3 = 0 ... x = -3/2
x - 3 = 0 ... x = 3
Find the zeros of the function algebraically. (Enter your answers as a comma-separated list.)
f(x) = 2x2 − 3x − 9
1 answer