There seems to be a typographical error in the given polynomial. It should be either "p(x) = x² - 6x + 16x" or "p(x) = x² - 6x - 16x". Assuming the former case:
p(x) = x² - 6x + 16x
= x² + 10x
= x(x + 10)
Therefore, the zeros of p(x) are x = 0 and x = -10.
Find the zeros of the following
A) p(x)= x²-6x²-16x
1 answer