To find the zeros of h(x), we need to find the values of x at which h(x) equals zero.
First, we can set each factor in h(x) equal to zero and solve for x:
-3x^2 = 0
This equation has a zero at x = 0.
5x + 8 = 0
Subtracting 8 from both sides, we get:
5x = -8
Dividing both sides by 5, we get:
x = -8/5
x - 6 = 0
Adding 6 to both sides, we get:
x = 6
So the zeros of h(x) are x = 0, x = -8/5, and x = 6.
Find the zeros of h(x). Show your work.
h(x) = -3x^2(5x+8)(x-6)
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