find the zeroes of g(x)=(x^2-5x-6)/(x^2-9)

Question

I know i suppose to use synthetic division, but the denominator has x^2 in it. Does this matter or do I just divide by -9

Answer 1

to divide by a polynomial with power other than 1 you have to use long divison.

However for this problem that's not necessary... just factor

G(x) = (x-2)(x-3)/(x-3)(x+3)

thus your only zero is x = 2 since the function is not defined at x = 3

Answer 2

{1,2,3}