Asked by rachael
find the x-values at which f is not continuous. which of the discontinuities are removable?
f(x)=1/(x^2+1)
f(x)=1/(x^2+1)
Answers
Answered by
Fredr
the function is not continuous when the denominator is zero, or...
0 = x^2+1
solving for x then
x = i
It is a removable discontinuity since it can be repaired by replacing a single point.
0 = x^2+1
solving for x then
x = i
It is a removable discontinuity since it can be repaired by replacing a single point.
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