Find the x-intercept of the equation below. You must show ALL work to earn full credit.

Question

8x+4y=16

Answer 1

To find the x-intercept of the equation \(8x + 4y = 16\), we need to determine the value of \(x\) when \(y = 0\).

Here are the steps:

1. Substitute \(y = 0\) into the equation: \[ 8x + 4(0) = 16 \]

2. Simplify the equation: \[ 8x + 0 = 16 \] \[ 8x = 16 \]

3. Solve for \(x\): \[ x = \frac{16}{8} \] \[ x = 2 \]

The x-intercept is therefore at the point \((2, 0)\).

To summarize, the x-intercept of the equation \(8x + 4y = 16\) is: \[ \boxed{2} \]

Answer 2

this time find the y

Answer 3

To find the y-intercept of the equation \(8x + 4y = 16\), we need to determine the value of \(y\) when \(x = 0\).

Here are the steps:

1. Substitute \(x = 0\) into the equation: \[ 8(0) + 4y = 16 \]

2. Simplify the equation: \[ 0 + 4y = 16 \] \[ 4y = 16 \]

3. Solve for \(y\): \[ y = \frac{16}{4} \] \[ y = 4 \]

The y-intercept is therefore at the point \((0, 4)\).

To summarize, the y-intercept of the equation \(8x + 4y = 16\) is: \[ \boxed{4} \]