Find the​ x-intercept and the​ y-intercept of the graph of the equation.

Question

3x + 7y = 21

Answer 1

To find the x-intercept, we set y equal to 0 and solve for x:

3x + 7(0) = 21
3x = 21
x = 7

So the x-intercept is (7, 0).

To find the y-intercept, we set x equal to 0 and solve for y:

3(0) + 7y = 21
7y = 21
y = 3

So the y-intercept is (0, 3).

Answer 2

Find the​ x-intercept and the​ y-intercept of the graph of the equation.

4x + 2y = 16

Answer 3

To find the x-intercept, we set y equal to 0 and solve for x:

4x + 2(0) = 16
4x = 16
x = 4

So the x-intercept is (4, 0).

To find the y-intercept, we set x equal to 0 and solve for y:

4(0) + 2y = 16
2y = 16
y = 8

So the y-intercept is (0, 8).

Answer 4

Draw a line with the given intercepts.

x + y = -8

Answer 5

To draw the line with the x-intercept and y-intercept of the equation x + y = -8, we can use the intercepts we found:

x-intercept: (8, 0)
y-intercept: (0, -8)

Starting from the x-intercept (8, 0), we can move left 8 units (since y = 0) and upward 8 units (since x = 8) to reach the y-intercept (0, -8).

Plotting these points and connecting them with a straight line, we get:

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Answer 6

are you sure?

Answer 7

My apologies for the mistake. You are correct, the intercepts I provided earlier were not accurate for the equation x + y = -8. Let's recalculate the intercepts.

To find the x-intercept, we set y equal to 0 and solve for x:

x + 0 = -8
x = -8

So the x-intercept is (-8, 0).

To find the y-intercept, we set x equal to 0 and solve for y:

0 + y = -8
y = -8

So the y-intercept is (0, -8).

Plotting these points, we can draw a line passing through them:

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Answer 8

Graph the linear equation.

y = 5

Answer 9

The equation y = 5 represents a horizontal line passing through the y-coordinate 5.

To graph this linear equation, we can plot a point at y = 5 on the y-axis.

The graph would look like this:

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