use Pythagoras
w^2 + 48^2 = 50^2
solve for w
Find the width of a recctangle that has a length of 48 cm a diagonal of 50 cm.
2 answers
d = diagonal
L = Length
W = Width
d ^ 2 = L ^ 2 + W ^ 2
50 ^ 2 = 48 ^ 2 + W ^ 2
2500 = 2304 + W ^ 2 Subtract 2304 to both sides
2500 - 2304 = 2304 + W ^ 2 - 2304
196 = W ^ 2
W = sqrt ( 196 )
W = + OR - 14
Width can't be negative so
W = 14 cm
L = Length
W = Width
d ^ 2 = L ^ 2 + W ^ 2
50 ^ 2 = 48 ^ 2 + W ^ 2
2500 = 2304 + W ^ 2 Subtract 2304 to both sides
2500 - 2304 = 2304 + W ^ 2 - 2304
196 = W ^ 2
W = sqrt ( 196 )
W = + OR - 14
Width can't be negative so
W = 14 cm
3 answers