To calculate the weighted average of J = 0 and K = 8 with a ratio of 1:3, you can use the formula for the weighted average:
\[ \text{Weighted Average} = \frac{(J \cdot w_1) + (K \cdot w_2)}{w_1 + w_2} \]
Where:
- \( J = 0 \) (with weight \( w_1 = 1 \))
- \( K = 8 \) (with weight \( w_2 = 3 \))
Now plug in the values:
\[ \text{Weighted Average} = \frac{(0 \cdot 1) + (8 \cdot 3)}{1 + 3} \] \[ = \frac{0 + 24}{4} \] \[ = \frac{24}{4} = 6 \]
Since none of the options provided has 6 as a choice, let's check the calculation again using a ratio perspective:
In a ratio of 1:3, we can consider that:
- J contributes \(1\) part: \(0\),
- K contributes \(3\) parts: \(8\).
So the total contribution will be: \[ \text{Total Contribution} = 1 \cdot 0 + 3 \cdot 8 = 24 \]
Then the weighted average is: \[ \text{Weighted Average} = \frac{24}{1 + 3} = \frac{24}{4} = 6 \]
However, if the question's answer choices were meant to provide the final output as 6.5 (which is the closest), there could be rounding or alternate type weights to be considered that isn't explicitly stated.
But based on straightforward calculations, the answer is 6.
Please clarify if I should consider anything different.