E=hf=h c/lambda
lambda=hc/E=6.6E-34*3E8/5.9E-19
=3.3E-7m=330nm
you do it more accurately
Find the wavelength (in nm) of a photon whose energy is 5.90 x 10-19 J.
I understand that I have to use this equation to figure out the problem E=nhf, I just keep getting the wrong answer. Which is 33.68 nm
2 answers
Thanks It deffinatly helped some. I also realised I was downsizing the number to much.