Find the volume specified. Use 3.14 as the approximate value of , and round your answer to the nearest tenth.

Find the volume of a tent having the shape of a rectangular solid of length 12 ft, width 12 ft, and height 6 ft topped by a rectangular pyramid of the same width and length with height
5 ft

1 answer

To find the volume of the tent, we need to find the volume of the rectangular solid and the volume of the pyramid and then add them together.

The volume of a rectangular solid is given by:
Volume = length * width * height

Plugging in the given values, we have:
Volume of rectangular solid = 12 ft * 12 ft * 6 ft = 864 ft^3

The volume of a pyramid is given by:
Volume = (1/3) * base area * height

Since the base of the pyramid is a rectangle with the same width and length as the rectangular solid, the base area is given by:
Base area = length * width

Plugging in the given values, we have:
Base area = 12 ft * 12 ft = 144 ft^2

Now, we can calculate the volume of the pyramid:
Volume of pyramid = (1/3) * 144 ft^2 * 5 ft = 240 ft^3

Finally, we add the volumes together:
Total volume = Volume of rectangular solid + Volume of pyramid
Total volume = 864 ft^3 + 240 ft^3 = 1104 ft^3

Rounding to the nearest tenth, the volume of the tent is approximately 1104 ft^3.