Find the volume of the solid of revolution obtained by revolving the plane region R bounded by y= x^5, the y-axis, and the line y=3 about the x-axis
So far:
y=x^5 is equal to x=5th root y. I've plugged that in to pi(r^2)h, and got V = pi ∫[0,3] y^(2/5) dy.
so far I've gotten 15/7(3^(2/5))pi, but the system I'm using won't accept it. I don't even know if I'm doing this right, please help