vol = π∫y^2 dx from 0 to 1
= π∫16x^4 dx
= π[(16/5)x^5] from 0 to 1
= π(16/5 - 0] = 16π/5
Find the volume of the solid obtained by rotating the region bounded by
y=4x^2,x=1,y=0
about the x-axis.
2 answers
why is the intergral from 0 to 1