Hint: use the disk method
Find the intersection of x² and y=6, which is x=±sqrt(6).
You may want to integrate with x=-sqrt(6) to +sqrt(6)
πf(x)^2 dx [equiv. to πr²]
where
f(x)=x²-1 [i.e. from y=1 to y=x^2]
Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.
y = x2, y = 1; about y = 6
1 answer
1 answer