First you need their intersection, that should be easy
Hope you get (-2,5) and (1,2)
The outer radius is (3-x)
the inner radius is (x^2+1)
so you want ∫ ( (3-x)^2 - (x^2+1)^2 )dx from x = -2 to 1
expand and the rest is pretty straightforward.
Let me know what you get
Find the volume of the solid generated by revolving the region bounded by the given curves about the x-axis.
y=x^2+1
x+y=3
Please help me set up the integral!
2 answers
Awesome, that's what I got!