Asked by Josh
Find the volume of the solid formed by rotating the region enclosed by
y=e^(1x)+4, y=0, x=0 and x=0.2
about the x-axis?
Ty
y=e^(1x)+4, y=0, x=0 and x=0.2
about the x-axis?
Ty
Answers
Answered by
Reiny
can't tell if your equation is
y = e^(x+4)
or
y = e^x + 4 , why is there a 1 in front of the x ?
y = e^(x+4)
or
y = e^x + 4 , why is there a 1 in front of the x ?
Answered by
Josh
it is e^x + 4 not y = e^(x+4)
Sorry that was how the problem was worded.
Sorry that was how the problem was worded.
Answered by
Steve
the volume is just a stack of thin discs, of thickness dx, and radius y
So, the volume is the integral of
pi * y^2 dx
= pi*(e^2x + 8e^x + 16)
all pretty straightforward. C'mon back if you get stuck, and show where.
So, the volume is the integral of
pi * y^2 dx
= pi*(e^2x + 8e^x + 16)
all pretty straightforward. C'mon back if you get stuck, and show where.
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