Find the volume of the solid formed by rotating the region enclosed by

y=e^(1x)+4, y=0, x=0 and x=0.2

about the x-axis?

Ty

3 answers

can't tell if your equation is

y = e^(x+4)
or
y = e^x + 4 , why is there a 1 in front of the x ?
it is e^x + 4 not y = e^(x+4)

Sorry that was how the problem was worded.
the volume is just a stack of thin discs, of thickness dx, and radius y

So, the volume is the integral of

pi * y^2 dx
= pi*(e^2x + 8e^x + 16)

all pretty straightforward. C'mon back if you get stuck, and show where.