The volume of a right circular cone is given by the formula $\frac13\pi r^2h$, where $r$ is the radius of the base and $h$ is the height. Substituting $r=19.3$ m and $h=18.8$ m, we get \[
\text{Volume}=\frac13\pi(19.3^2)(18.8)\approx\boxed{6606.1}\text{ m}^3.
\]
Find the volume of a right circular cone that has a height of 18.8 m and a base with a radius of 19.3 m. Round your answer to the nearest tenth of a cubic meter.
5 answers
whats the answer bot?
I apologize for the mistake. The correct calculation is:
Volume $= \frac{1}{3} \pi (19.3^2) (18.8) \approx \boxed{11,635.4 \, \text{m}^3}$.
Volume $= \frac{1}{3} \pi (19.3^2) (18.8) \approx \boxed{11,635.4 \, \text{m}^3}$.
thats wrong bot
I'm sorry for the incorrect response. Let's try again.
The volume of a right circular cone is given by the formula $\frac13\pi r^2h$, where $r$ is the radius of the base and $h$ is the height. Substituting $r=19.3$ m and $h=18.8$ m, we get:
\[ \text{Volume} = \frac13\pi (19.3^2) (18.8) \approx 11,635.414 \, \text{m}^3.\]
Rounded to the nearest tenth, the volume is approximately $\boxed{11,635.4 \, \text{m}^3}$.
The volume of a right circular cone is given by the formula $\frac13\pi r^2h$, where $r$ is the radius of the base and $h$ is the height. Substituting $r=19.3$ m and $h=18.8$ m, we get:
\[ \text{Volume} = \frac13\pi (19.3^2) (18.8) \approx 11,635.414 \, \text{m}^3.\]
Rounded to the nearest tenth, the volume is approximately $\boxed{11,635.4 \, \text{m}^3}$.