To find the volume of the figure, we can use the formula V = lwh where l is the length, w is the width, and h is the height.
Given:
Length (l) = 1 in
Width (w) = 6.2 in
Height (h) = 2 in
Plugging in the values, we have:
V = (1 in)(6.2 in)(2 in)
V = 12.4 in³
Therefore, the volume of the figure is 12.4 cubic inches.
To find the surface area of the figure, we need to calculate the area of each face and then add them together.
The figure consists of six faces: 2 identical faces with dimensions 1 in by 6.2 in, 2 identical faces with dimensions 1 in by 2 in, and 2 identical faces with dimensions 6.2 in by 2 in.
The area of a rectangle is given by the formula A = lw, where A is the area, l is the length, and w is the width.
For the faces with dimensions 1 in by 6.2 in:
A = (1 in)(6.2 in) = 6.2 in²
Since there are 2 identical faces, the total area is:
2 * 6.2 in² = 12.4 in²
For the faces with dimensions 1 in by 2 in:
A = (1 in)(2 in) = 2 in²
Since there are 2 identical faces, the total area is:
2 * 2 in² = 4 in²
For the faces with dimensions 6.2 in by 2 in:
A = (6.2 in)(2 in) = 12.4 in²
Since there are 2 identical faces, the total area is:
2 * 12.4 in² = 24.8 in²
Adding up the areas of all the faces:
12.4 in² + 4 in² + 24.8 in² = 41.2 in²
Therefore, the surface area of the figure is 41.2 square inches.
Find the volume and surface area of the figure.
1 in 6.2 in 2 in
1 answer