To find the vertical asymptotes of the function y = (x^2 + 8x + 12) / (x^2 - 9), we need to determine the values of x where the denominator is equal to zero (since division by zero is undefined).
Setting the denominator equal to zero:
x^2 - 9 = 0
(x + 3)(x - 3) = 0
This gives us two possible vertical asymptotes at x = 3 and x = -3.
Therefore, the vertical asymptotes of the function are x = 3 and x = -3.
Find the vertical asymptotes of this function: y= x2+8x+12 x2−9 <---- You must show your work and enter your answer below.
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