To analyze the rational function \( h(x) = \frac{x + 3}{x(x - 6)} \), we need to identify the vertical asymptotes and any holes in the graph.
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Identifying Vertical Asymptotes: Vertical asymptotes occur where the denominator is zero and the numerator is not zero at those points.
The denominator is \( x(x - 6) = 0 \) which can be factored to find the roots: \[ x = 0 \quad \text{or} \quad x - 6 = 0 \Rightarrow x = 6 \]
We will check the numerator at these values:
- For \( x = 0 \): \[ h(0) = \frac{0 + 3}{0(0 - 6)} = \text{undefined (denominator is zero)} \]
- For \( x = 6 \): \[ h(6) = \frac{6 + 3}{6(6 - 6)} = \text{undefined (denominator is zero)} \]
Both points \( x = 0 \) and \( x = 6 \) result in undefined values and are vertical asymptotes.
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Identifying Holes: Holes occur if the same factor in the numerator and denominator cancels each other.
The numerator \( x + 3 \) has no common factors with \( x \) or \( x - 6 \), thus there are no holes.
Putting it all together, our results are:
- Vertical asymptotes at \( x = 0 \) and \( x = 6 \).
- No holes.
Based on the choices given, the correct selection is:
A. The vertical asymptote(s) is(are) \( x = 0, x = 6 \) and hole(s) corresponding to none.