Asked by LaH
Find the values of x and y that maximize or minimize the objective function.
x+y < or equal to 8
2x+y < or equal to 10
x> or equal to 0, y > or equal to 0
A. (0,5) Maximum value is 100
B.(1,7) Maximum value is 220
C.(2,6) Maximum value is 280
D. (5,0) Maximum value is 400
I'm so confused. Please help.
x+y < or equal to 8
2x+y < or equal to 10
x> or equal to 0, y > or equal to 0
A. (0,5) Maximum value is 100
B.(1,7) Maximum value is 220
C.(2,6) Maximum value is 280
D. (5,0) Maximum value is 400
I'm so confused. Please help.
Answers
Answered by
LaH
Sorry, I forgot to add the objective function.
C=80x+20y
C=80x+20y
Answered by
Bill G
Probably a little late, but this is how you solve it:
You are given two formulas:
x + y = 8
2x + y = 10
First manipulate them so that you have a common variable alone. I did:
y = 8 - x
y = 10 - 2x
Since y = y you can combine these formulas to create:
8 - x = 10 - 2x
Solve this to find x.
x = 2
Plug x into one of the original formulas:
(x) + y = 8
(2) + y = 8
Solve for y.
y = 6
You now have x and y.
(2,6)
Plug x and y into the objective function:
C = 80(x) + 20(y)
C = 80(2) + 20(6)
Solve for C.
C = 160 + 120
C = 280
You have your answer:
C.(2,6) Maximum value is 280
You are given two formulas:
x + y = 8
2x + y = 10
First manipulate them so that you have a common variable alone. I did:
y = 8 - x
y = 10 - 2x
Since y = y you can combine these formulas to create:
8 - x = 10 - 2x
Solve this to find x.
x = 2
Plug x into one of the original formulas:
(x) + y = 8
(2) + y = 8
Solve for y.
y = 6
You now have x and y.
(2,6)
Plug x and y into the objective function:
C = 80(x) + 20(y)
C = 80(2) + 20(6)
Solve for C.
C = 160 + 120
C = 280
You have your answer:
C.(2,6) Maximum value is 280
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