the only place where your function f(x) = 6/(x-3) is not continuous is at x= 3
your interval does not reach that value, so recall your definition of the Mean Value Theorem.
A series of YouTube clips that are done by Sal Khan offer really simple explanations.
Here is the one that deals with this topic.
http://www.youtube.com/watch?v=bGNMXfaNR5Q
Find the values of c that satisfy the Mean Value Theorem for f(x)=6/x-3 on the interval [-1,2].
Is it no value of c in that interval because the function is not continuous on that interval???
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