Find the values of a, b, and c such that the equation y=ax^2+bx+c has ordered pair solutions (-3,-22), (-1,2) and (3,2)


a = 2; b = 8; d = 4

a = -2; b = 4; c = 8

a = 2; b = 4; c = 8

a = -2; b = 8; c = 4

1 answer

lazy way: try the points to see whether they fit.

algebraic way. Plug in the values for x and y to get

9a-3b+c = -22
a-b+c = 2
9a+3b+c = 2

Either way, it's -2,4,8