find the value value of X

Question

m<AOB=4x-2, m<BOC=5x+10 m<COD=3x-8

Answer 1

m<AOE = 180 and M<BOC and m<DOE are congruent angles
So

m<AOB + m<BOC + m<COD + m<DOE = 180

(4x-2)+(5x+10)+(3x-8)+(5x+10) = 180

17x+10=180

17x = 170

x = 170

Answer 2

m<AOE = 180 and M<BOC and m<DOE are congruent angles
So

m<AOB + m<BOC + m<COD + m<DOE = 180

(4x-2)+(5x+10)+(3x-8)+(5x+10) = 180

17x+10=180

17x=170

x=10

Answer 3

the person is wrong