Find the value of x to the nearest tenth.

hypotenuse: 42
side b: 32

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1 answer

This appears to be a right triangle, where the hypotenuse is opposite to the right angle and side b is adjacent to one of the acute angles. We can use the Pythagorean theorem to find the missing side, x, which is also adjacent to the same angle as side b.

According to the Pythagorean theorem, in a right triangle,

c^2 = a^2 + b^2

where c is the length of the hypotenuse and a and b are the lengths of the other two sides.

Substituting the given values, we get:

42^2 = x^2 + 32^2

1764 = x^2 + 1024

Subtracting 1024 from both sides, we get:

740 = x^2

Taking the square root of both sides, we get:

x ≈ 27.2 (rounded to the nearest tenth)

Therefore, the value of x to the nearest tenth is approximately 27.2 units.