In a right triangle, if we know one acute angle and the hypotenuse, we can use trigonometric ratios to find the lengths of the other sides.
In this case, we know the hypotenuse is 16 and angle B is 72 degrees. We want to find the length of side a opposite angle B.
Using the trigonometric ratio for sine:
sin B = opposite/hypotenuse
sin 72 = a/16
a = 16 sin 72
a ≈ 15.2 (rounded to the nearest tenth)
Therefore, x (the length of side a) is approximately 15.2 to the nearest tenth.
Find the value of x to the nearest tenth.
hypotenuse: 16
angle b: 72°
you should get 15.2
show work.
please answer
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